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# Find the derivative of $\frac{x^5-x^4+x^2-2}{x^2+1}$

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##  Final answer to the problem

$\frac{3x^{6}+5x^{4}-2x^{5}-4x^{3}+6x}{\left(x^2+1\right)^2}$
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##  Step-by-step Solution 

How should I solve this problem?

• Find the derivative
• Find the derivative using the definition
• Find the derivative using the product rule
• Find the derivative using the quotient rule
• Find the derivative using logarithmic differentiation
• Integrate by partial fractions
• Product of Binomials with Common Term
• FOIL Method
• Integrate by substitution
• Integrate by parts
Can't find a method? Tell us so we can add it.
1

Apply the quotient rule for differentiation, which states that if $f(x)$ and $g(x)$ are functions and $h(x)$ is the function defined by ${\displaystyle h(x) = \frac{f(x)}{g(x)}}$, where ${g(x) \neq 0}$, then ${\displaystyle h'(x) = \frac{f'(x) \cdot g(x) - g'(x) \cdot f(x)}{g(x)^2}}$

$\frac{\frac{d}{dx}\left(x^5-x^4+x^2-2\right)\left(x^2+1\right)-\left(x^5-x^4+x^2-2\right)\frac{d}{dx}\left(x^2+1\right)}{\left(x^2+1\right)^2}$
2

Simplify the product $-(x^5-x^4+x^2-2)$

$\frac{\frac{d}{dx}\left(x^5-x^4+x^2-2\right)\left(x^2+1\right)+\left(-x^5-\left(-x^4+x^2-2\right)\right)\frac{d}{dx}\left(x^2+1\right)}{\left(x^2+1\right)^2}$
3

Simplify the product $-(-x^4+x^2-2)$

$\frac{\frac{d}{dx}\left(x^5-x^4+x^2-2\right)\left(x^2+1\right)+\left(-x^5+x^4-\left(x^2-2\right)\right)\frac{d}{dx}\left(x^2+1\right)}{\left(x^2+1\right)^2}$
4

Simplify the product $-(x^2-2)$

$\frac{\frac{d}{dx}\left(x^5-x^4+x^2-2\right)\left(x^2+1\right)+\left(-x^5+x^4-x^2+2\right)\frac{d}{dx}\left(x^2+1\right)}{\left(x^2+1\right)^2}$
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5

The derivative of a sum of two or more functions is the sum of the derivatives of each function

$\frac{\left(\frac{d}{dx}\left(x^5\right)+\frac{d}{dx}\left(-x^4\right)+\frac{d}{dx}\left(x^2\right)+\frac{d}{dx}\left(-2\right)\right)\left(x^2+1\right)+\left(-x^5+x^4-x^2+2\right)\frac{d}{dx}\left(x^2+1\right)}{\left(x^2+1\right)^2}$
6

The derivative of a sum of two or more functions is the sum of the derivatives of each function

$\frac{\left(\frac{d}{dx}\left(x^5\right)+\frac{d}{dx}\left(-x^4\right)+\frac{d}{dx}\left(x^2\right)+\frac{d}{dx}\left(-2\right)\right)\left(x^2+1\right)+\left(-x^5+x^4-x^2+2\right)\left(\frac{d}{dx}\left(x^2\right)+\frac{d}{dx}\left(1\right)\right)}{\left(x^2+1\right)^2}$
7

The derivative of the constant function ($-2$) is equal to zero

$\frac{\left(\frac{d}{dx}\left(x^5\right)+\frac{d}{dx}\left(-x^4\right)+\frac{d}{dx}\left(x^2\right)\right)\left(x^2+1\right)+\left(-x^5+x^4-x^2+2\right)\left(\frac{d}{dx}\left(x^2\right)+\frac{d}{dx}\left(1\right)\right)}{\left(x^2+1\right)^2}$
8

The derivative of the constant function ($1$) is equal to zero

$\frac{\left(\frac{d}{dx}\left(x^5\right)+\frac{d}{dx}\left(-x^4\right)+\frac{d}{dx}\left(x^2\right)\right)\left(x^2+1\right)+\left(-x^5+x^4-x^2+2\right)\frac{d}{dx}\left(x^2\right)}{\left(x^2+1\right)^2}$
9

The derivative of a function multiplied by a constant is equal to the constant times the derivative of the function

$\frac{\left(\frac{d}{dx}\left(x^5\right)-\frac{d}{dx}\left(x^4\right)+\frac{d}{dx}\left(x^2\right)\right)\left(x^2+1\right)+\left(-x^5+x^4-x^2+2\right)\frac{d}{dx}\left(x^2\right)}{\left(x^2+1\right)^2}$
10

The power rule for differentiation states that if $n$ is a real number and $f(x) = x^n$, then $f'(x) = nx^{n-1}$

$\frac{\left(5x^{4}-4x^{3}+2x\right)\left(x^2+1\right)+2\left(-x^5+x^4-x^2+2\right)x}{\left(x^2+1\right)^2}$
11

Simplify the derivative

$\frac{3x^{6}+5x^{4}-2x^{5}-4x^{3}+6x}{\left(x^2+1\right)^2}$

##  Final answer to the problem

$\frac{3x^{6}+5x^{4}-2x^{5}-4x^{3}+6x}{\left(x^2+1\right)^2}$

##  Explore different ways to solve this problem

Solving a math problem using different methods is important because it enhances understanding, encourages critical thinking, allows for multiple solutions, and develops problem-solving strategies. Read more

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e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

###  Main Topic: Differential Calculus

The derivative of a function of a real variable measures the sensitivity to change of a quantity (a function value or dependent variable) which is determined by another quantity (the independent variable). Derivatives are a fundamental tool of calculus.