$\frac{\left(tan\theta\:+1\right)^2-sec^2\theta\:}{tan\theta\:}=2$

$-g+-5g-3g$

$5x\left(3x+5\right)=6\left(2x-8\right)$

$\left(x+4\right)\left(3x+6\right)$

$\cot\left(x\right)+4\cos\left(x\right)\cot\left(x\right)=0$

$10\:-\:3\left(0.75\right)\:-\:2\left(0.50\right)$

$\int tan^5\left(8x\right)sec^2\left(8x\right)dx$