$\frac{\cos}{\sec}\cdot\tan^2=\sin^2$
$\frac{8}{v}=\frac{12}{v+3}$
$2ax-3bx+2ay-3by$
$\sqrt[3]{a^9}b^{12}c^{15}$
$y=\ln\frac{1+x^2}{1-x^2}$
$-4\cdot\left(1+7\right)$
$\int\left(x\right)\sec^2\left(x^2\right)\tan^4\left(x^2\right)dx$
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