$x^{2+18x-9}$
$\frac{6x^3-3x^2-8}{2x+3}$
$12x\:+\:4x$
$\frac{1-cot^2\left(x\right)}{1+cot^2\left(x\right)}=sin^2\left(x\right)-cos^2\left(x\right)$
$75-3x^2$
$\frac{d}{dx}\frac{4}{x-4}=x^2+1$
$\frac{x^2-9}{-6x^2-18}$
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