$3x+4y-z;\:x=3;y=-1yz=4$
$\sqrt[2]{2\:.\:2\:.\:9}$
$\frac{dy}{dx}\left(x^2+y^2=r^2\right)$
$\left(12b+7^2\right)$
$\left(60.50\right)^5+\left(0.40\right)^{12}$
$8\left(-11+2\right)-3\left(+12-6\right)$
$\int9\:csc\:x\:dx$
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