$12-7^3$
$\frac{8x^5+4x^3+12x^2+2x+16}{2x^3+x^2+3}$
$\int_{-1}^1\arctan\left(x\right)dx$
$y'+5xy=0$
$7x^2y^4+12x^2y^4-8x^2y^4-17x^2y^4$
$-3x^2y+2xy\left(-5x^3y+4x^2y\right)\left(7xy+7\right)$
$4\cdot\left|31+\left(-69\right)\right|$
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