$3x^3+12x^2+6xes$

$\lim_{x\to4}\left(\frac{\left(f+4\right)\left(f-2\right)^2}{\left(3t-6\right)^2}\right)$

$\int\left(\frac{20x+5}{\left(5x+5\right)^3}\right)dx$

$-4-\left(-6-3\right):\left(-2-1\right)$

$-6\left(3w+1\right)+-3\left(4w-2\right)$

$\left(4x^3-2y\right)^3$

$x+10+x+12$