$y'=\frac{1}{\left(x+3\right)^2}$
$a-\frac{1}{a}=\sqrt{3}$
$5-x^{2}<-2$
$3.25-789.50$
$4\left(x^2\:+\:5\right)\:-\:10y$
$\frac{126x^4+81y^4}{2x+3y}$
$\int\frac{\sqrt{x^2-1}}{\sqrt{x^4}}dx$
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