$\left(2x\:+\:3y\:+\:4\right)\:dx\:=\:\left(4x\:+\:6y\:+\:1\right)\:dy$
$\left(\frac{\frac{1}{x+1}-\frac{1}{3}}{x-2}\right)$
$\lim_{x\to\infty}\left(\frac{3x^2+5}{x^2+x-3}\right)$
$\sqrt[2]{x^2+16}=5$
$4x^2-6x=0$
$\frac{dy}{dx}=-2\:\cdot\left(\frac{1}{e^y}\right)\cdot\sin\left(x\right)$
$x^4-3x^3-14x^2+48x-32$
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