$\left(6a-1\right)^2$
$\frac{1}{\cos\left(x\right)^2}-1=\tan\left(x\right)^2$
$\left(\sin^2\left(x\right)-1\right)\left(\sec^2\left(x\right)-1\right)$
$7x\:-\:3\:-\:19\:+\:5x$
$1+cot2xsin2x=1$
$\left(x^2-2x+1\right)\left(x+1\right)$
$\:\frac{\left(-3\right)^n}{n}\left(x-2\right)^n$
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