$9-3x+2x\left(6x-2\right)+\left(4x+1\right)\left(2x-1\right)$
$\lim_{x\to\infty}\left(\frac{x}{1+x}\right)$
$x^2-x-56<0$
$\frac{x^2+4x+6}{x+2}$
$\frac{dy}{dx}=\frac{x}{e^x}$
$-a+4a$
$\left(3a^2-3b\right)\left(9a^4+9a^2b+9b^2\right)$
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