$\left(9a^5+6c^2\right)^3$
$\int\frac{x^2-5x+10}{\left(3x+9\right)\left(x^2+5\right)}dx$
$\left(4x^ay^b\right)\left(9x^2y^3\right)$
$x^2-5x+-25=0$
$y ( t ) = \frac { ( x t ) ^ { 2 } + t y } { ( x t ) ^ { 3 } }$
$\left(y^{-2}\right)^{-3}$
$\frac{x^2}{2}+x$
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