$\tan^3\left(x\right)=\frac{3\tan\left(x\right)-\tan^2\left(x\right)}{1-3\tan^2\left(x\right)}$

$\int\frac{x^3}{\sqrt{x^2+2}}dx$

$-9x^2-6x-5$

$\int_1^{\infty}\left(\frac{1}{1+cosx}\right)dx$

$\frac{d}{dy}y$

$\int\:\left(\sqrt[4]{x}+2\right)\left(3-\sqrt{x}\right)dx$

$\frac{x}{2}+\frac{x}{5}-9=x+\frac{3}{10}$