$\frac{9}{3}$
$-\left(x+4\right)=-x+y$
$\int\frac{x-6}{\left(x+3\right)\left(2x-5\right)}dx$
$\left(x-y\right)\left(dx-dy\right)=0$
$\int\left(2x-5\right)\left(x-3\right)^9dx$
$\left(s+1\right)\left(s+5\right)\left(s-3\right)$
$y=\frac{-20}{x^2+x^3}$
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