$\frac{6d^6}{3d^3}$
$y'-y^2=1$
$-3n=-9$
$-4157\:+360$
$\int\frac{x^2+8x+1}{x^3+2x^2-x-2}dx$
$x^3\:+\:y^3\:=\:\left(x\:+\:y\right)\left(x^2\:-\:xy\:+\:y^2\right)$
$\log_{10}\left(3x-2\right)-\log_{10}\left(x\right)=0$
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