$\cos\left(\theta\right)=-1$
$\frac{2}{8}+8x$
$\left(n^5-4n^4+2n^3+8\right)\left(-2n^2\right)$
$2x\:a\:la\:3$
$n^2-6+9$
$n^2-17=-2n$
$3\left(x+12\right)=5x+10$
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