$\frac{2x^3-4x^2+3x-7}{x}$
$3.14\left(\frac{5^2}{6^2}\right)\left(\frac{16}{5}\right)$
$12\left(\frac{600}{1}\right)\left(\frac{480}{60}\right)$
$\int\frac{4}{\left(x-3\right)^2}dx$
$\int\frac{6x^2}{\sqrt{x^3}-1}dx$
$-4+5\left(-4+2\right)-6-3\cdot\left(2-4\right)$
$4\left(3\right)^4-4\left(-2\right)^4$
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