$\frac{x^2+6x+12}{x-4}$
$cos\:a\:\left(1-sin\:a\right)\left(1+sin\:a\right)$
$3\tan\left(8\pi\right)\left(x\right)=-\sqrt{3}$
$-9\:y-18$
$x^3\sqrt{x^2}$
$13+5d+6y-d-y-2$
$f\left(x\right)=\left(4x^3+6\right)\left(\sqrt{x}+8\right)$
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