$\frac{\sqrt[4]{y^3+8}-\:\sqrt{2+y}}{y-2}$

$\frac{\sin\left(x\right)+\cos\left(x\right)}{\tan\left(x\right)\cdot\cot\left(x\right)}\:=\:\sin\left(x\right)+\cos\left(x\right)$

$\sqrt{4x^2}\sqrt{9^2}$

$x^2\left(9x^2\right)$

$789+32-34$

$4x+1<13$

$f\left(x\right)=\left(8-x\right)\left(\frac{4}{x^2}-9\right)$