$\left(2x^2-3x+4\right)^2$
$\left(9a^5b^8-17a^3b^2\right)$
$6+a=15$
$\int_0^{4\cos\left(y\right)}\left(\sqrt{16-x^2}x\right)dx$
$\int\left(\frac{1}{x\left(4+lnx\right)}\right)dx$
$-2,36-2,5$
$\cos\left(4x\right)=0$
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