$\lim_{x\to\infty}\left(\frac{7x^2+4}{3-4x}\right)$
$\frac{16x^2-25m^2n^4}{5mn^2+4x}$
$\left(x-21\right)^2$
$4x-y=-9$
$2\sin\left(7x\right)=1$
$y^2-9y-20$
$\frac{x+2}{x^3-1}\:-\:\frac{1}{x+1}$
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