$\lim_{x\to0}\left(\frac{ln^{\frac{1}{x}}}{\frac{1}{tanx}}\right)$

$\int\frac{x^2-9}{\left(x-1\right)\left(x^2-1\right)}dx$

$\lim_{x\to0}\left(\frac{1+sinx}{\left(\arctan\left(x\right)\right)}-e^x\right)$

$4x^2-24+36$

$1-\sin^2x=\frac{1}{\csc^2\left(x\right)}$

$7+\left(-2-\left(-5+8\right)\right)$

$5.52\cdot0.4+5.45\cdot0.4$