$9x+5>23$
$\left(2x^2+x\:+1\right)^2$
$\left(3-x\right)\left(3+\right)$
$\frac{\sqrt{x}+3}{x^2\left(x-9\right)}$
$\sqrt{3}\sec\left(x+2\right)=0$
$7x^2-4x+5.3x+4$
$4^2-12x+9$
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