$\int e^{10x+8}dx$
$9x^2+48x-64$
$16m^3d^2-100$
$\frac { \pi } { 0 }$
$2-4+\left(-2+1\right)+5-\left[3-\left(1-2\right)+4\right]+1-2$
$\:\left(5x^3\right)^2$
$\frac{dx}{dt}=\frac{2x}{40-t}$
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