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Exercise

$\frac{x+3}{6}=\frac{x+1}{x-4}$

Final answer to the exercise

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Other solved exercises

$\frac{dy}{dx}=8x\sqrt{3y+9}$

$6x+5>4x+11$

$y^2-8y-20=0$

$5\left(\sqrt{z}-3\right)^2$

$\left(-5\right)\cdot\left(4+9\right)$

$x+3=10$

$2.5\cdot5$
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