$\int\frac{3}{\left(x-4\right)\left(x^2+2x+6\right)}dx$
$\frac{du}{dx}+u=-e^x$
$\left|\left(-13\right)+\left(+15\right)\right|$
$\int\frac{1}{\:x^2+2x}dx$
$\log_{\left(x+4\right)}\left(x^2-3x-5\right)=\frac{3}{4}$
$ln\:y'=x$
$\sqrt[5]{x^3}.\sqrt{x}$
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