$\lim_{x\to-\infty}\left(\frac{3x+1}{3x+4}\right)^{\left(\frac{2x^2+1}{x-3}\right)}$
$\frac{16-x^{16}}{2-x^4}$
$\frac{2}{7}=\frac{b+1}{56}$
$\int\frac{x+19}{x^2-2x-15}dx$
$\frac{4x^5}{x^3}+\left(-3x^2\right)$
$x=3\tan\left(y\right)$
$\int\sin\left(6x\right)\cos\left(4x\right)dx$
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