$x^2-2x-3\le0$
$\lim_{x\to0}\left(\frac{1-\cos\left(2x\right)}{4x}\right)$
$\frac{1}{\sqrt{4x-3-x^2}}$
$\frac{x^3y^{-2}}{z^2}$
$2x^2+14x-36$
$4z^2y^3x^3+8z^5x^2+9z^6x^5$
$9x^2+6x+64$
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