$\left(\frac{cos\left(x\right)}{sin\left(x\right)+1}\right)$
$\left(-56.04\right)+\left(-39.1\right)$
$\lim_{x\to\frac{1}{2}}\left(\frac{4-32x^3}{1-4x^2}\right)$
$3x+3\le-1$
$\frac{25m^6n^4-4}{5m^3n^2-2}$
$-8+3-7+5$
$sinx+sin4x=0$
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