$4\left(x^2+5x-5\right)^3\left(2x+5\right)$

$-4a\:+\:5a\:-\:2a\:$

$\lim_{x\to2}\left(\frac{\left(x-1\right)^3}{2x-4}\right)$

$\int\sin\ln\left(3x\right)dx$

$0^{3}\sqrt{17\cdot\left(-2\right)^{5}-\left(-2\right)^{5}}-\left(-6^{3}+\left(-6\right)^{0}\right):\left(-5\right)+\left(-7\right)^{2}$

$\frac{2x-1}{3}<\frac{-x+2}{4}-2$

$4\left(8\right)^2-4\left(8\right)-24$