$\frac{2\tan\left(\frac{x}{2}\right)}{1+tan^2\left(\frac{x}{2}\right)}=sinx$
$a^2-16ab+64b^2$
$-14\:\left(-5\right)\:+\:5\:$
$\left(a+x\right)\sqrt{a+x}$
$x^4+8x^3+21x^2+22x+8$
$\int\:\frac{1}{\left(16-x^2\right)^{\frac{3}{2}}}dx$
$\frac{dx}{dy}=\frac{x^3y}{1+x^2}$
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