$\frac{6x^2+17x+12}{3x+4}$
$\int-3\cos\left(\frac{x}{3}\right)dx$
$-321\:-\:987$
$\int\frac{2}{x^{-10}}dx$
$\frac{x^3-18x+3}{x-4}$
$+5+\left(+4+\left(-8-3+\left(-8-4+6+7+8\right)-9\right)\right)$
$\log\left(x\right)=\log\left(x+3\right)-\log\left(x-1\right)$
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