$\frac{5}{4}x+6-3x-4$
$-68\:-\:74\:+\:90\:-\:43\:-\:17\:+\:30\:-\:12$
$x^2-bx$
$\frac{d}{dx}\left(\frac{1}{x}+\frac{1}{y}\right)=1$
$w^2-5w+\frac{25}{5}$
$f\left(x\right)=\left(6x^3-4x\right)\left(3x+x^4\right)$
$-2\cdot41+3$
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