$\frac{\sin^3\left(x\right)\left(1+\frac{1}{\tan^2\left(x\right)}\right)}{\sec\left(x\right).\tan\left(x\right)}$
$\left(xy^2\:+\:3x\right)dx\:+\:y\sqrt{x^2+9}dy\:=\:0$
$\frac{160x\:-36}{5x+3}$
$16\left(16\right)$
$8\:x\:0.135\left\{\right\}$
$\lim_{x\to\infty}\left(\frac{x^2-1}{x}\right)^{\frac{1}{3x}}$
$x=\sqrt{x^2-10x+25}$
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