$\int\left(3\sin^3\left(x\right)\right)dx$
$\left|6-8\right|.\left(-2\right)$
$14x^2-20x+6$
$\left(2p^5q\right)\left(-13px^5\right)\left(-pq^4r^3x\right)$
$-1^1$
$\frac{x^4-3x^2+2}{x-1}$
$-4\sqrt{x^3}$
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