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Exercise

$\frac{m^{2}-6m+4}{m^{2}-m-4}\cdot\frac{m^{2}+2m}{m^{2}+2m-15}$

Step-by-step Solution

1

Multiplying fractions $\frac{m^2-6m+4}{m^2-m-4} \times \frac{m^2+2m}{m^2+2m-15}$

$\frac{\left(m^2-6m+4\right)\left(m^2+2m\right)}{\left(m^2-m-4\right)\left(m^2+2m-15\right)}$

Final answer to the exercise

$\frac{\left(m^2-6m+4\right)\left(m^2+2m\right)}{\left(m^2-m-4\right)\left(m^2+2m-15\right)}$

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