$\frac { x ^ { 2 } + x - 6 } { x + 3 } = x - 2$
$10^{-1}>\sqrt{0.01}$
$11\left(2x-7\right)+2\left(5x-4\right)-3\left(2x-5\right)=-18$
$3senx=-1$
$\left(a+b-4\right)x\left(a-b+2\right)=0$
$4mn^3+2m^2$
$x^5-x^4-34x$
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