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Exercise

$\frac{dz}{dx}\left(\left(z^2+6xy\right)\left(\sqrt{x^3+5}\right)=2\right)$

Step-by-step Solution

1

Applicare la formula: $x\left(a+b\right)$$=xa+xb$, dove $a=z^2$, $b=6xy$, $x=\sqrt{x^3+5}$ e $a+b=z^2+6xy$

$\frac{dz}{dx}\sqrt{x^3+5}z^2+6\sqrt{x^3+5}xy=2$

Final answer to the exercise

$\frac{dz}{dx}\sqrt{x^3+5}z^2+6\sqrt{x^3+5}xy=2$

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