$\lim_{x\to0}\left(\frac{2^{sinx}-1}{2x}\right)$
$x^2-6x+1x$
$\frac{10x^5-4x^4+8x^3+6x^2-5x+11}{2x^2-2x+4}$
$-463-200$
$\frac{\sqrt{z^5}}{\sqrt[3]{z^x}}$
$20x^3+90x^2-80x+36$
$-\left|-7\right|=-7$
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