$\int\left(x^2\left(5x^3-1\right)^6\right)dx$
$\int_{\frac{\pi}{6}}^{\frac{\pi^2}{6}}\left(tan\left(t\right)\right)dt$
$\left(2p+3\right)^4$
$4y^3-5x^3-1-4x^3-6+7+5y^3$
$\left(-6\left(-4\left(3\right)\right)\right)$
$58\cdot52$
$4x+3y=18$
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