$x^2-3x-20\le0$
$3x^2-25=0$
$\left(-8\right)\cdot\left(-10\right)\cdot\left(-5\right)$
$\lim_{x\to-2}\left(\frac{x^3-8}{x^2-4}\right)$
$\frac{x^0y^{-3}}{y^5}$
$f\left(x\right)=\frac{13}{x^2-5-36}$
$\frac{3^4\cdot3^3\cdot3^{-2}}{3^{-3}\cdot3^0\cdot3^2}$
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