$2\left(2x+1\right)+3\left(x-1\right)$
$x^{\frac{4}{6}}$
$\sqrt{x}+1=\sqrt{x+9}$
$3^2+6x-10$
$-\left(11\right)\left(-11\right)\left(-1\right)$
$3x^2-18x+81$
$\frac{3}{8}x^3+\frac{9}{7}x^3$
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