$14+x=18$
$-2y^2\:+y^3$
$\sqrt{c}+\frac{1}{\sqrt{c}}^2$
$3y+6x$
$\frac{d}{dx}\left(x^4=e^{-3x^4-10y^5}\right)$
$\int\frac{1}{\sqrt{x}\left(\sqrt{x}-2\right)}dx$
$\cot\left(x\right)=-\frac{5}{7}$
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