$x^8+5x^4+4=\left(x^4\:+4i\right)\left(x^4-i\right)$
$\left(x+3\right)^2+\left(x-3\right)^2-6<0$
$3\left(8x\:+\:1\right)\:+\:q$
$12\:-\:x\:\le9$
$3e^{xy}-x=0$
$5x+12\:con\:x\:=2,5$
$+8\left(x+3\right)=m\cdotn$
Get a preview of step-by-step solutions.
Earn solution credits, which you can redeem for complete step-by-step solutions.
Save your favorite problems.
Become premium to access unlimited solutions, download solutions, discounts and more!