$\left(2x^4+3y^2-1\right)\left(5x^3+6x\right)$
$-3+7+1-4+5-12+9$
$\frac{x^3}{x^8}$
$\left(-43\right)\left(-52\right)$
$\int\frac{\left(9x-13\right)}{3x^2-11x+6}dx$
$x^3+2x^2y-3ax\left(x+1\right)$
$\left(6+4\right)^2-10$
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