$x^2-8=-1$
$0.12345\cdot100$
$\frac{\left(xy\left(4\right)\right)}{xy}^3$
$\left(10\right)\left(-5\right)\left(-4\right)\left(8\right)$
$\left(10\right)\left(-9\right)\left(-3\right)\left(-11\right)$
$\frac{72}{9}$
$\frac{2x^4-x^3+7x-3}{x+3}$
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