$\int_1^{\infty}\left(1-x\right)e^{-\infty}dx$
$4y-6y-4y$
$\left(4x-3\right)\left(x+3\right)$
$-125\cdot8$
$2x^4-4x^3+6x$
$\frac{10h^5k^3}{24h^{-2}}$
$\left(x\right)\left(x-1\right)\left(x-5\right)$
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