$\frac{3x}{10}-\frac{2}{5}<\frac{6x}{5}-\frac{3}{2}$

$\left(2a-b+6c\right)^2$

$\left(5x-7y-5\right)\left(7x\right)$

$\frac{\left(1-sinx\right)^2}{1-sin^2x}=\frac{1-sinx}{sinx+1}$

$\frac{3x}{x+2}+6x+4=\frac{12}{x^2+2x}$

$\left(-99.143\right)+100.743+100.204+\left(-99.020\right)+100.357+100.175+100.337+100.123+100.289+100.102+100.066+100.066+\left(-99.007\right)+\left(-99.018\right)+100.476+100.785+\left(-99.311\right)+\left(-99.225\right)+\left(-99.225\right)+\left(-99.087\right)$

$\left(d^3\right)^{-11}$