$\left(9z\:+5\right)\left(9z-5\right)$
$x+6>4-3x$
$3\left(c\:-9\right)\:-\:7\left(c\:+1\right)\:+\:2\left(c\:+\:4\right)$
$\left(4a^3b^2c^2+3a^2b^3c^3\right)^3$
$85+48x+x^2$
$\left(3x^2-\frac{5}{8}\right)\left(3x^2+\frac{5}{8}\right)$
$2x+1\:+\:2x-1$
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