$3\left(7-5\right)^2+\left(20-19\right)^2+14$

$4m-4n$

$\frac{tan\left(x+y\right)-tan\left(x\right)}{1+tan\left(x+y\right)\cdot\:\:tan\left(x\right)}=tan\left(y\right)$

$\frac{4x^3-2x^2-14x-2}{2x+3}$

$\:\int_{58}^{100}\pi\left(\left(-.12\right)\left(y-100\right)\right)^2dy$

$y'=\:y^2-4$

$8m^327n^3^2$